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a) The sum of their
squares is minimum
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when
x is one of the numbers the other is (7.5-2x)
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The
function to be minimised is f(x)=x2+(7.5-2x)2
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Find
f'(x) and solve the equation: f'(x)=0
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Find
f''(x) and its sign at these values.
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Make
the parameter "a" equal to 1, then change the value of x in the window
and check your results.
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b)
The
difference between their squares is maximum.
- Which is the
function we need to maximise
now?
- Follow the same
steps as above.
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Now
use the CLEAR button and make the parameter
"a" equal to -1.
Change the value of x and check your results.
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